Identify the final product D of the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Step $1$: Electrophilic addition of $Br_2$ to propene gives $1,2-dibromopropane$ $(A)$: $CH_3-CH(Br)-CH_2Br$.Step $2$: Dehydrohalogenation with $3

Vedclass · Accepted Answer

$cis-CH_3-CH=CH-CH_3$

Vedclass · Answer

(D) Step $1$: Electrophilic addition of $Br_2$ to propene gives $1,2-dibromopropane$ $(A)$: $CH_3-CH(Br)-CH_2Br$.Step $2$: Dehydrohalogenation with $3 \ mol$ of $NaNH_2$ removes $2 \ mol$ of $HBr$ to form propyne $(B)$: $CH_3-C \equiv CH$.Step $3$: $NaNH_2$ deprotonates the terminal alkyne to form an acetylide ion, which reacts with $CH_3-Br$ via $S_N2$ to form $but-2-yne$ $(C)$: $CH_3-C \equiv C-CH_3$.Step $4$: Lindlar's catalyst $(Pd-BaSO_4)$ performs syn-hydrogenation of the alkyne to form $cis-but-2-ene$ $(D)$: $cis-CH_3-CH=CH-CH_3$.The correct option is $D$.

Identify the final product $D$ of the following reaction sequence:
$CH_3-CH=CH_2 \xrightarrow[CCl_4]{Br_2} A \xrightarrow[(3 \ mol)]{NaNH_2} B \xrightarrow{CH_3-Br} C \xrightarrow[Pd-BaSO_4]{H_2} D$

Similar Questions

Number of acidic hydrogen atoms in $but-1-yne$ are

Ethylidene dichloride is obtained by the reaction of excess of $HCl$ with

Silver acetylide when heated with $HCl$ gives:

Acetylene gives

Number of possible alkynes with formula $C_{5}H_{8}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify the final product $D$ of the following reaction sequence:$CH_3-CH=CH_2 \xrightarrow[CCl_4]{Br_2} A \xrightarrow[(3 \ mol)]{NaNH_2} B \xrightarrow{CH_3-Br} C \xrightarrow[Pd-BaSO_4]{H_2} D$